∑ Old Books, New Math

Lesson 7 · from §102 of the 1910 text

Geometrical Problems

Geometrical problems

The circumference of a circle is 2\pi R, R being the radius. In these problems use \dfrac{22}{7} for \pi. The area of a circle is \pi R^2.

A wheel moves forward one circumference in each revolution, so the number of revolutions is the distance divided by the circumference.

Two chords

If any two chords of a circle, AC and DE, cross at B, then AB \times BC = DB \times BE.

ACDEB

A perpendicular to a diameter

If AB is a line drawn from a point on the circumference perpendicular to the diameter CD of the circle, then AB \cdot AB = CB \cdot BD.

CDBA

Give lengths as numbers, or in simplest radical form where a root is irrational (for example 10sqrt(2)).

Try one:

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Quick check

A wheel 7 feet in circumference rolls 35 yards. How many revolutions does it make?

revolutions
From the history of algebra

History of the quadratic equation. Though the development of the method of solving quadratic equations is closely connected with the general growth of algebra, it is possible to indicate the most important steps in the process rather briefly.

The first writer on formal algebra was Diophantos, who lived at Alexandria, in Egypt, about 300 A.D. Most of his work that is preserved is devoted to the solution of problems that lead to equations. So far as we know he was the first to indicate the unknown number by a single letter, in this respect being far in advance of many mathematicians who lived much later. It is a little remarkable, in fact, that so able and original a man as Diophantos should have exerted so little influence on his successors. He solved his quadratic equations by a method not unlike that of completing the square, but his imperfect knowledge of the nature of numbers made it impossible for him to understand the entire significance of the process. Though he made every effort not to consider equations whose roots were not positive integers, sometimes they would creep in, and under such circumstances, when his method led him to a negative or irrational root, he rejected the whole equation as absurd or impossible. Even when both of the roots were positive he took only the one afforded by the positive sign in the formula for solving a quadratic.

The difficulties of Diophantos are typical of those encountered by mathematicians for the next fifteen hundred years. The difficulty lay, not in finding a formal method of solving the equation, but in understanding the result after it was obtained. The meanings of negative and of imaginary numbers have been two of the most difficult of all mathematical ideas for men to grasp.

Five or six hundred years later the Hindus devised a general solution of the quadratic, but their chief advance over Diophantos lay in the fact that they did not regard an equation whose roots were negative as necessarily absurd, but merely rejected the negative result of solving such an equation with the remark, "It is inadequate; people do not approve of negative roots." The Hindus, however, did realize that a quadratic equation sometimes has two roots, a fact that Diophantos never comprehended. They even went so far as to illustrate the difference between positive and negative numbers by assets and debts.

No material gain in the understanding of the solutions of the quadratic can be found until the seventeenth century. The keenest mathematicians of the sixteenth century, like Cardan and Vieta, rejected negative solutions regularly, though by this time irrational numbers were admitted. In fact, in 1544 Stifel, a German, published an algebra in which irrational numbers are included among the numbers proper. But he affirms that except in the case where a quadratic equation has two positive roots, no equation has more than one root. It was not until the work of Descartes and Gauss became widely known that the nature of the roots of all kinds of quadratic equations was completely understood.

Exercises

0 of 11 solved
How to type math

Use ^ for powers (a^2), / for fractions ((a+b)/2), sqrt(x) for square roots, and cbrt(x) for cube roots. You can leave out the multiplication sign: 3ab means 3 \cdot a \cdot b. Mixed numbers like 4 1/2 work too. The preview under each box shows how your answer was read.

1

The circumference of a carriage wheel is 11 feet. How many revolutions will it make while the carriage goes 55 yards?

revolutions
2

The radius of a carriage wheel is 2 feet. How many revolutions does the wheel make while the carriage goes 132 yards?

revolutions
3

The circumference of a fore wheel of a carriage is 2 feet less than that of a rear wheel. In going 140 yards the smaller wheel makes 5 revolutions more than the larger. Find the circumference of each wheel.

feet
feet
4

In going 100 yards a fore wheel of a carriage makes 5 revolutions more than one of the rear wheels. The circumference of one wheel is 2 feet less than that of the other. Find the circumference and the radius of each wheel.

feet
feet
feet
feet
5

The circumferences of two wheels of a wagon differ by 2 feet. Together the two wheels make 11 revolutions while the wagon goes a distance of 20 yards. Find the diameter of each wheel.

feet
feet
6

The radii of two circles differ by 7 inches, and their areas differ by 770 square inches. Find their radii.

inches
inches

Use the figures in the lesson.

7

In the figure of the two chords, AC = 18, DB = 4, and BE = 20. Find AB.

8

In the figure of the two chords, AC = 5 feet, DB = 18 inches, and BE = 48 inches. Find AB and BC in feet.

9

In the figure of the perpendicular, AB = 9 and CD = 30. Find CB and BD.

10

In the figure of the perpendicular, AB = 20 and CB = 2BD. Find BD.

11

A line AB is 12 inches long. A point P is located on AB so that AB : AP = AP : PB. Find the length of AP. (Can a meaning be given to both answers?)