Lesson 6 · from §92 of the 1910 text
Simplest Form of a Radical
Simplification of radicals
The form of a radical expression may be changed without altering its value: \dfrac{1}{\sqrt2} can be changed to \dfrac{\sqrt2}{2}, for each equals .707\ldots
Study these changes of form:
- \sqrt{36} = \sqrt{4 \cdot 9} = \sqrt4 \cdot \sqrt9 = 2 \cdot 3 = 6.
- \sqrt8 = \sqrt{4 \cdot 2} = \sqrt4 \cdot \sqrt2 = 2\sqrt2.
- More generally, \sqrt{a^2b} = \sqrt{a^2}\sqrt b = a\sqrt b.
- \sqrt[3]{24} = \sqrt[3]{8 \cdot 3} = \sqrt[3]{8}\,\sqrt[3]{3} = 2\sqrt[3]{3}, and in general \sqrt[n]{a^nb} = a\sqrt[n]{b}.
A radical is in its simplest form when the radicand
- (a) is integral (no fraction under the radical sign),
- (b) contains no factor raised to a power equal to, or greater than, the order of the radical, and
- (c) is not raised to a power unless the exponent of the power and the index of the root are prime to each other.
The answer checker holds you to these rules: \sqrt{12} is marked "equal, but not in simplest form", and so is \dfrac{1}{\sqrt2}, because it leaves a radical in the denominator. Write 2\sqrt3 and \dfrac{\sqrt2}{2}. It also asks you to put a product of radicals under one sign: \sqrt{2}\cdot\sqrt{x} is written \sqrt{2x}.
Of (a), an integral radicand. Multiply both terms of the fraction under the sign so that the denominator becomes a perfect power: \sqrt{\tfrac23} = \sqrt{\tfrac69} = \tfrac13\sqrt6, \qquad \sqrt[3]{\tfrac{2}{9}} = \sqrt[3]{\tfrac{6}{27}} = \tfrac13\sqrt[3]{6}, \qquad \sqrt{\frac{a}{2b}} = \sqrt{\frac{2ab}{4b^2}} = \frac{1}{2b}\sqrt{2ab}.
Of (b), no factor to too high a power. Take out every factor whose power can be divided by the index: \sqrt{48} = \sqrt{16 \cdot 3} = 4\sqrt3, \qquad \sqrt[3]{16a^4} = \sqrt[3]{8a^3 \cdot 2a} = 2a\sqrt[3]{2a}.
Of (c), the index and the power prime to each other. Divide the index and the exponent by a common factor: \sqrt[4]{9} = \sqrt[4]{3^2} = 3^{2/4} = 3^{1/2} = \sqrt3, \qquad \sqrt[6]{27x^3} = \sqrt[6]{(3x)^3} = \sqrt{3x}.
An expression under a radical must be simplified as a whole first: \sqrt{1 + \left(\tfrac12\right)^2} = \sqrt{\tfrac54} = \tfrac12\sqrt5, and \sqrt{a^2 + \left(\tfrac a3\right)^2} = \sqrt{\tfrac{10a^2}{9}} = \tfrac a3\sqrt{10}.
How to type radicals
- Square root:
sqrt(12)or√12; a coefficient goes in front:2sqrt(3)or2√3. - Cube root:
cbrt(5)or∛5. Any other root:root(x, 4)for \sqrt[4]{x},root(2, 6)for \sqrt[6]{2}. - Put the whole radicand in parentheses when it is more than one number or letter:
sqrt(2x),cbrt(a + b),sqrt(2 - sqrt(2)). - Fractional exponents use
^with parentheses:x^(2/3). - Letters under a radical sign stand for positive numbers, so \sqrt{x^2} = x.
From the history of algebra
The Arabs could by no means state all the rules of this chapter, but they did recognize a few of them. A writer of about 830 A.D. gives, in his own notation, the facts contained in the formulas a\sqrt b = \sqrt{a^2b} and \sqrt a\,\sqrt b = \sqrt{ab}.
Exercises
How to type math
Use ^ for powers (a^2), / for fractions ((a+b)/2), sqrt(x) for square roots, and cbrt(x) for cube roots. You can leave out the multiplication sign: 3ab means 3 \cdot a \cdot b. Mixed numbers like 4 1/2 work too. The preview under each box shows how your answer was read.
Express in simplest form:
\sqrt{12}
\sqrt{32}
\sqrt{75}
2\sqrt{50}
\sqrt[3]{40}
\sqrt[3]{54}
\sqrt{20}
\sqrt[3]{3000}
2\sqrt[3]{24}
\sqrt{\tfrac12}
\sqrt{\tfrac25}
\sqrt{\tfrac38}
3\sqrt{\tfrac92}
5\sqrt{\tfrac35}
\sqrt[3]{\tfrac12}
4\sqrt[3]{\tfrac14}
8\sqrt[3]{\tfrac74}
\sqrt{1 - \left(\tfrac12\right)^2}
\sqrt{1 + \left(\tfrac13\right)^2}
\sqrt{2 + \left(\tfrac35\right)^2}
\sqrt[3]{1 - \left(\tfrac12\right)^2}
\sqrt[3]{4 + \left(\tfrac23\right)^2}
\sqrt[3]{1 + \left(\tfrac13\right)^3}
\sqrt[4]{25a^2}
3\sqrt{4x^5}
a\sqrt[6]{8x^3}
x\sqrt[4]{49a^2x^2}
\sqrt[6]{125x^{3a}y^{3m}}
\sqrt{\dfrac{a^3}{27}}
a\sqrt[3]{\dfrac{5}{2a^2}}
\sqrt{R^2 - \left(\dfrac R2\right)^2}
\sqrt{R^2 + \left(\dfrac R2\right)^2}
\sqrt{\left(a + \dfrac a3\right)\left(a - \dfrac a3\right)}
\sqrt[3]{R^3 - \left(\dfrac R2\right)^3}
(x - y)\sqrt{\dfrac{x + y}{x - y}}